ReflectionMethod::invokeArgs()

(PHP 5 >= 5.1.2, PHP 7)

带参数执行

说明

publicReflectionMethod::invokeArgs(object $object, array $args) : mixed

使用数组给方法传送参数，并执行他。

参数

$object

调用方法的对象，如果是静态对象，设置为null

$args

使用array传送的方法参数。

返回值

返回方法返回值

错误／异常

如果$object指定的实例无法执行方法，那么产生ReflectionException异常。

如果方法调用失败，产生ReflectionException

范例

Example #1ReflectionMethod::invokeArgs()example

<?php
class HelloWorld {
    public function sayHelloTo($name) {
        return 'Hello ' . $name;
    }
}
$reflectionMethod = new ReflectionMethod('HelloWorld', 'sayHelloTo');
echo $reflectionMethod->invokeArgs(new HelloWorld(), array('Mike'));
?>

以上例程会输出：

Hello Mike

注释

Note:

如果函数有参数需为引用，那么它们必须以引用方式传入。

参见

• ReflectionMethod::invoke() Invoke
• __invoke()
• call_user_func_array()调用回调函数，并把一个数组参数作为回调函数的参数

We can do black magic, which is useful in templating block calls:
<?php
   $object->__named('methodNameHere', array('arg3' => 'three', 'arg1' => 'one'));
   ...
   /**
    * Pass method arguments by name
    *
    * @param string $method
    * @param array $args
    * @return mixed
    */
   public function __named($method, array $args = array())
   {
    $reflection = new ReflectionMethod($this, $method);
    $pass = array();
    foreach($reflection->getParameters() as $param)
    {
     /* @var $param ReflectionParameter */
     if(isset($args[$param->getName()]))
     {
      $pass[] = $args[$param->getName()];
     }
     else
     {
      $pass[] = $param->getDefaultValue();
     }
    }
    return $reflection->invokeArgs($this, $pass);
   }
?>

If you need to call ReflectionMethod::invokeArgs() on a static function you can pass NULL in for the $object parameter.
Example:
<?php
   class myClass {
     public static myStaticFunc($a, $b) {
        return $a + $b;
     }
   }
   $ref = new ReflectionMethod('myClass', 'myStaticFunc');
   echo $ref->invokeArgs(NULL, [12, 7]);
?>
produces the following output:
19

There is a simple workaround for the reference passing problem:
Since the reflection api has to handle all parameters in a generic way it has no chance to guess if you wish to pass data per value or reference.
But it seems that you can also decide to pass a reference from where you call the function or method (not just only by the ampersand prefix in its declaration).
So just do the following; which worked for me:
<?php
//...
$method->invoke($object, $inputValue, &$outputValue);
?>
Since this will only be necessary with arrays and primitive data types it should be acceptable in most cases to know in advance if you need to pass per reference. But it is probably although necessary to keep the ampersand always in the declaration (because of the at least two layers between the actual function and your invoke call).
If this is the expected behavior it will maybe make sense to mention it in the documentation for invoke and invokeArgs.

Passing arguments by reference works:
<?php $rm->invokeArgs($object, array(&$foo, $bar)); ?>