unref()如果参数是 ref,则返回内部值,否则返回参数本身。这是一个语法糖函数val = isRef(val) ? val.value : val类型 function unref<T>(ref: T | Ref<T>): T 例子 function useFoo(x: number | Ref<number>) { const unwrapped = unref(x) // unwrapped is guaranteed to be number now }