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  • mysql_select_db()

    (PHP 4, PHP 5)

    选择 MySQL 数据库

    说明

    mysql_select_db(string $database_name[,resource$ link_identifier]): bool

    成功时返回TRUE,或者在失败时返回FALSE

    mysql_select_db()设定与指定的连接标识符所关联的服务器上的当前激活数据库。如果没有指定连接标识符,则使用上一个打开的连接。如果没有打开的连接,本函数将无参数调用mysql_connect()来尝试打开一个并使用之。

    每个其后的mysql_query()调用都会作用于活动数据库。

    Example #1 mysql_select_db()例子

    <?php
    $lnk = mysql_connect('localhost', 'mysql_user', 'mysql_password')
           or die ('Not connected : ' . mysql_error());
    // make foo the current db
    mysql_select_db('foo', $lnk) or die ('Can\'t use foo : ' . mysql_error());
    ?>
    

    参见mysql_connect(),mysql_pconnect()和mysql_query()。

    为向下兼容仍然可以使用mysql_selectdb(),但反对这样做。

    参数

    $database_name

    The name of the database that is to be selected.

    $link_identifier

    MySQL连接。如不指定连接标识,则使用由mysql_connect()最近打开的连接。如果没有找到该连接,会尝试不带参数调用mysql_connect()来创建。如没有找到连接或无法建立连接,则会生成E_WARNING级别的错误。

    返回值

    成功时返回TRUE,或者在失败时返回FALSE

    范例

    Example #2 mysql_select_db() example

    <?php
    $link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
    if (!$link) {
        die('Not connected : ' . mysql_error());
    }
    // make foo the current db
    $db_selected = mysql_select_db('foo', $link);
    if (!$db_selected) {
        die ('Can\'t use foo : ' . mysql_error());
    }
    ?>
    

    注释

    Note:

    为了向下兼容,可以使用下列已废弃的别名:mysql_selectdb()

    参见

    Be carefull if you are using two databases on the same server at the same time. By default mysql_connect returns the same connection ID for multiple calls with the same server parameters, which means if you do 
    <?php
     $db1 = mysql_connect(...stuff...);
     $db2 = mysql_connect(...stuff...);
     mysql_select_db('db1', $db1);
     mysql_select_db('db2', $db2); 
    ?>
    then $db1 will actually have selected the database 'db2', because the second call to mysql_connect just returned the already opened connection ID !
    You have two options here, eiher you have to call mysql_select_db before each query you do, or if you're using php4.2+ there is a parameter to mysql_connect to force the creation of a new link.
    About opening connections if the same parameters to mysql_connect() are used: this can be avoided by using the 'new_link' parameter to that function.
    This parameter has been available since PHP 4.2.0 and allows you to open a new link even if the call uses the same parameters.
    function go_mysql($query)
    {
      global $mysql_link; 
      
      if (!$mysql_link)
      {
        $mysql_link = mysql_connect("localhost","root","my_pass") or die(mysql_error());
        mysql_select_db("my_db") or die(mysql_error());
        mysql_query("SET NAMES 'utf8'");
        mysql_query("set character_set_client='utf8'");
        mysql_query("set character_set_results='utf8'");
        mysql_query("set collation_connection='utf8'");
        global $mysql_link;
      }
        
      $result=mysql_query($query);
      if ($result)
      {
        return $result;
      }
      else
      {
        echo "Database Error: " . mysql_error()."<br><b>$query</b>";
        die();
      }
    }
    Cross-database join queries, expanding on Dan Ross's post...
    Really, this is a mysql specific feature, but worth noting here. So long as the mysql user has been given the right permissions to all databases and tables where data is pulled from or pushed to, this will work. Though the mysql_select_db function selects one database, the mysql statement may reference another (the syntax for referencing a field in another db table being 'database.table.field').
    <?php
    $sql_statement = "SELECT
      PostID,
      AuthorID,
      Users.tblUsers.Username
      FROM tblPosts
      LEFT JOIN Users.tblUsers ON AuthorID = Users.tblUsers.UserID
      GROUP BY PostID,AuthorID,Username
      ";
    $dblink = mysql_connect("somehost", "someuser", "password");
    mysql_select_db("BlogPosts",$dblink);
    $qry = mysql_query($sql_statement,$dblink);
    ?>
    
    You can select MySQL database without using this function.
    Simply right after connecting to MySQL
    <?php $connection = mysql_connect("dabatbasehost", "username", "password"); ?>
    perform this query:
    <?php mysql_query("USE somedatabase", $connection); ?>
    
    Note that the manual is slightly misleading it states :-
    "Sets the current active database on the server that's associated with the specified link identifier. Every subsequent call to mysql_query() will be made on the active database."
    The 2nd statement is not true or at best unclear.
    mysql_query() manual entry actually correctly states it will use the last link opened by mysql_connect() by default.
    Thus if you have 2 connections you will need to specify the connection when calling mysql_query or issue the connect again to ensure the 1st database becomes the default, simply using mysql_select_db will not make the 1st database the default for subsequent calls to mysql_query.
    Its probably only apparent when the two databases are on different servers.
    Problem with connecting to multiple databases within the same server is that every time you do:
    mysql_connect(host, username, passwd);
    it will reuse 'Resource id' for every connection, which means you will end with only one connection reference to avoid that do:
    mysql_connect(host, username, passwd, true);
    keeps all connections separate.
    You can use DataBases without <?php mysql_select_db() ?>
    And you will havenot james at gogo dot co dot nz's problems :)
    <?php
    mysql_connect('localhost','db_user','pssword');
    mysql_query('SELECT * FROM database_name.table_name');
    ?>