$argv

传递给脚本的参数数组

说明

包含当运行于命令行下时传递给当前脚本的参数的数组。

Note:第一个参数总是当前脚本的文件名，因此$argv[0]就是脚本文件名。

Note:这个变量仅在register_argc_argv打开时可用。

范例

Example #1$argv范例

<?php
var_dump($argv);
?>

当使用这个命令执行：php script.php arg1 arg2 arg3

以上例程的输出类似于：

array(4) {
  [0]=>
  string(10) "script.php"
  [1]=>
  string(4) "arg1"
  [2]=>
  string(4) "arg2"
  [3]=>
  string(4) "arg3"
}

参见

• getopt()从命令行参数列表中获取选项

Please note that, $argv and $argc need to be declared global, while trying to access within a class method. 
<?php
class A
{
  public static function b()
  {
    var_dump($argv);
    var_dump(isset($argv));
  }
}
A::b();
?>
will output NULL bool(false) with a notice of "Undefined variable ..."
whereas global $argv fixes that.

To use $_GET so you dont need to support both if it could be used from command line and from web browser.
foreach ($argv as $arg) {
  $e=explode("=",$arg);
  if(count($e)==2)
    $_GET[$e[0]]=$e[1];
  else  
    $_GET[$e[0]]=0;
}

Sometimes $argv can be null, such as when "register-argc-argv" is set to false. In some cases I've found the variable is populated correctly when running "php-cli" instead of just "php" from the command line (or cron).

If you come from a shell scripting background, you might expect to find this topic under the heading "positional parameters".