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  • cal_days_in_month()

    (PHP 4 >= 4.1.0, PHP 5, PHP 7)

    返回某个历法中某年中某月的天数

    说明

    cal_days_in_month(int $calendar,int $month,int $year): int

    该函数返回特定历法中的某中的某的天数。

    参数

    $calendar

    用来计算的某个历法

    $month

    选定历法中的某月

    $year

    选定历法中的某年

    返回值

    指定历法中选定的某月的天数。

    范例

    cal_days_in_month() example

    <?php
    $num = cal_days_in_month(CAL_GREGORIAN, 8, 2003); // 31
    echo "There was $num days in August 2003";
    ?>
    
    Remember if you just want the days in the current month, use the date function:
    $days = date("t");
    Here's a one-line function I just wrote to find the numbers of days in a month that doesn't depend on any other functions.
    The reason I made this is because I just found out I forgot to compile PHP with support for calendars, and a class I'm writing for my website's open source section was broken. So rather than recompiling PHP (which I will get around to tomorrow I guess), I just wrote this function which should work just as well, and will always work without the requirement of PHP's calendar extension or any other PHP functions for that matter.
    I learned the days of the month using the old knuckle & inbetween knuckle method, so that should explain the mod 7 part. :)
    <?php
    /*
     * days_in_month($month, $year)
     * Returns the number of days in a given month and year, taking into account leap years.
     *
     * $month: numeric month (integers 1-12)
     * $year: numeric year (any integer)
     *
     * Prec: $month is an integer between 1 and 12, inclusive, and $year is an integer.
     * Post: none
     */
    // corrected by ben at sparkyb dot net
    function days_in_month($month, $year)
    {
    // calculate number of days in a month
    return $month == 2 ? ($year % 4 ? 28 : ($year % 100 ? 29 : ($year % 400 ? 28 : 29))) : (($month - 1) % 7 % 2 ? 30 : 31);
    }
    ?>
    Enjoy,
    David Bindel
    This will work great in future dates but will give the wrong answer for dates before 1550 (approx) when leap year was introduced and the calendar lost a year or two.
    Sorry now to be more specific it has been a while sine I had to account for those later dates and had to take that into account but just a heads up for others to watch out.
    <?php
    # PHP Calendar (version 2.3), written by Keith Devens
    function generate_calendar($year, $month, $days = array(), $day_name_length = 3, $month_href = NULL, $first_day = 0, $pn = array()){
      $first_of_month = gmmktime(0,0,0,$month,1,$year);
      #remember that mktime will automatically correct if invalid dates are entered
      # for instance, mktime(0,0,0,12,32,1997) will be the date for Jan 1, 1998
      # this provides a built in "rounding" feature to generate_calendar()
      $day_names = array(); #generate all the day names according to the current locale
      for($n=0,$t=(3+$first_day)*86400; $n<7; $n++,$t+=86400) #January 4, 1970 was a Sunday
        $day_names[$n] = ucfirst(gmstrftime('%A',$t)); #%A means full textual day name
      list($month, $year, $month_name, $weekday) = explode(',',gmstrftime('%m,%Y,%B,%w',$first_of_month));
      $weekday = ($weekday + 7 - $first_day) % 7; #adjust for $first_day
      $title  = htmlentities(ucfirst($month_name)).'&nbsp;'.$year; #note that some locales don't capitalize month and day names
      #Begin calendar. Uses a real <caption>. See http://diveintomark.org/archives/2002/07/03
      @list($p, $pl) = each($pn); @list($n, $nl) = each($pn); #previous and next links, if applicable
      if($p) $p = '<span class="calendar-prev">'.($pl ? '<a href="'.htmlspecialchars($pl).'">'.$p.'</a>' : $p).'</span>&nbsp;';
      if($n) $n = '&nbsp;<span class="calendar-next">'.($nl ? '<a href="'.htmlspecialchars($nl).'">'.$n.'</a>' : $n).'</span>';
      $calendar = '<table class="calendar">'."\n".
        '<caption class="calendar-month">'.$p.($month_href ? '<a href="'.htmlspecialchars($month_href).'">'.$title.'</a>' : $title).$n."</caption>\n<tr>";
      if($day_name_length){ #if the day names should be shown ($day_name_length > 0)
        #if day_name_length is >3, the full name of the day will be printed
        foreach($day_names as $d)
          $calendar .= '<th abbr="'.htmlentities($d).'">'.htmlentities($day_name_length < 4 ? substr($d,0,$day_name_length) : $d).'</th>';
        $calendar .= "</tr>\n<tr>";
      }
      if($weekday > 0) $calendar .= '<td colspan="'.$weekday.'">&nbsp;</td>'; #initial 'empty' days
      for($day=1,$days_in_month=gmdate('t',$first_of_month); $day<=$days_in_month; $day++,$weekday++){
        if($weekday == 7){
          $weekday  = 0; #start a new week
          $calendar .= "</tr>\n<tr>";
        }
        if(isset($days[$day]) and is_array($days[$day])){
          @list($link, $classes, $content) = $days[$day];
          if(is_null($content)) $content = $day;
          $calendar .= '<td'.($classes ? ' class="'.htmlspecialchars($classes).'">' : '>').
            ($link ? '<a href="'.htmlspecialchars($link).'">'.$content.'</a>' : $content).'</td>';
        }
        else $calendar .= "<td>$day</td>";
      }
      if($weekday != 7) $calendar .= '<td colspan="'.(7-$weekday).'">&nbsp;</td>'; #remaining "empty" days
      return $calendar."</tr>\n</table>\n";
    }
    echo generate_calendar(2010, 12, 16,3,NULL,0,15, $first_of_month, $day_names, $day_names[$n]);
    #echo generate_calendar($year, $month, $days,$day_name_length,$month_href,$first_day,$pn);
    ?>
    

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