jdtounix()
(PHP 4, PHP 5, PHP 7)
转变Julian Day计数为一个Unix时间戳
说明
jdtounix(int $jday): int
这个函数根据给定的julian天数返回一个Unix时间戳,或如果参数$jday不在Unix时间(Gregorian历法的1970年至2037年,或2440588 <=$jday<= 2465342)范围内返回FALSE
。返回的时间是本地时间(不是GMT)。
参数
- $jday
一个在 2440588 到 2465342 之间的julian天数
返回值
指定的julian天数的开始时的时间戳。
参见
unixtojd()
转变Unix时间戳为Julian Day计数
If you need an easy way to convert a decimal julian day to an unix timestamp you can use: $unixTimeStamp = ($julianDay - 2440587.5) * 86400; 2440587.5 is the julian day at 1/1/1970 0:00 UTC 86400 is the number of seconds in a day
Warning: the calender functions involving julian day operations seem to ignore the decimal part of the julian day count. This means that the returned date is wrong 50% of the time, since a julian day starts at decimal .5 . Take care!!
Remember that unixtojd() assumes your timestamp is in GMT, but jdtounix() returns a timestamp in localtime. This fooled me a few times. So if you have: $timestamp1 = time(); $timestamp2 = jdtounix(unixtojd($timestamp1)); Unless your localtime is the same as GMT, $timestamp1 will not equal $timestamp2.
Remember that UNIX timestamps indicate a number of seconds from midnight of January 1, 1970 on the Gregorian calendar, not the Julian Calendar.
unixtojd() assumes that your timestamp is in GMT, but jdtounix() returns a timestamp in localtime. so <?php $d1=jdtogregorian(unixtojd(time())); $d2= gmdate("m/d/Y"); $d3=date("m/d/Y"); ?> $d1 always equals $d2 but $d1 may differ from $d3