gzeof()

(PHP 4, PHP 5, PHP 7)

Test for EOF on a gz-file pointer

说明

gzeof(resource $zp): int

Tests the given GZ file pointer for EOF.

参数

$zp

The gz-file pointer. It must be valid, and must point to a file successfully opened by gzopen().

返回值

Returns TRUE if the gz-file pointer is at EOF or an error occurs; otherwise returns FALSE.

范例

gzeof() example

<?php
$gz = gzopen('somefile.gz', 'r');
while (!gzeof($gz)) {
  echo gzgetc($gz);
}
gzclose($gz);
?>

Be careful with this example. if gzopen doesn't return a valid handler, gzeof will do a nice loop.

<?php
#fixed example 
$gz = gzopen('somefile.gz', 'r');
while ($gz && !gzeof($gz)) {
 echo gzgetc($gz);
}
gzclose($gz);
?>