gzeof()
(PHP 4, PHP 5, PHP 7)
Test for EOF on a gz-file pointer
说明
gzeof(resource $zp): int
Tests the given GZ file pointer for EOF.
参数
- $zp
The gz-file pointer. It must be valid, and must point to a file successfully opened by gzopen().
返回值
Returns TRUE
if the gz-file pointer is at EOF or an error occurs; otherwise returns FALSE
.
范例
gzeof() example
<?php $gz = gzopen('somefile.gz', 'r'); while (!gzeof($gz)) { echo gzgetc($gz); } gzclose($gz); ?>
Be careful with this example. if gzopen doesn't return a valid handler, gzeof will do a nice loop.
<?php #fixed example $gz = gzopen('somefile.gz', 'r'); while ($gz && !gzeof($gz)) { echo gzgetc($gz); } gzclose($gz); ?>