gzgets()

(PHP 4, PHP 5, PHP 7)

Get line from file pointer

说明

gzgets(resource $zp[,int $length]): string

Gets a(uncompressed)string of up to length - 1 bytes read from the given file pointer. Reading ends when length - 1 bytes have been read, on a newline, or on EOF(whichever comes first).

参数

$zp

The gz-file pointer. It must be valid, and must point to a file successfully opened by gzopen().

$length

The length of data to get.

返回值

The uncompressed string, or FALSE on error.

范例

gzgets() example

<?php
$handle = gzopen('somefile.gz', 'r');
while (!gzeof($handle)) {
   $buffer = gzgets($handle, 4096);
   echo $buffer;
}
gzclose($handle);
?>

参见

• gzopen()Open gz-file
• gzgetc()Get character from gz-file pointer
• gzwrite()Binary-safe gz-file write

<?
// this is simple code by VIJAY to unzip .gz file
$file = "/absolute/path/to/your/file" ;
$fp = fopen("$file", "w") ;
// file to be unzipped on your server
$filename = "filename.gz" ;
$zp = gzopen($filename, "r");
if ($zp)
{
 while (!gzeof($zp))
 {
  $buff1 = gzgets ($zp, 4096) ;
  fputs($fp, $buff1) ;
 }        
}      
gzclose($zp) ;
fclose($fp) ;
?>

PS when it encounters and breaks on a newline byte ("\n"), the newline byte itself is not included in the returned string.

For the above example by VIJAY, using gzgetc would be better, as I've encountered binary/text file incompatibilities (at least with PHP 4.0.4).