tidyNode::hasChildren()
(PHP 5, PHP 7)
检查节点是否有子节点
说明
public tidyNode::hasChildren(void): bool
返回值
Returns TRUE if the node has children,FALSE otherwise.
范例
tidyNode::hasChildren() example
<?php
$html = <<< HTML
<html><head>
<?php echo '<title>title</title>'; ?>
<#
/* JSTE code */
alert('Hello World');
#>
</head>
<body>
<?php
// PHP code
echo 'hello world!';
?>
<%
/* ASP code */
response.write("Hello World!")
%>
<!-- Comments -->
Hello World
</body></html>
Outside HTML
HTML;
$tidy = tidy_parse_string($html);
$num = 0;
// the head tag
var_dump($tidy->html() >child[0]->hasChildren());
// the php inside the head tag
var_dump($tidy->html() >child[0]->child[0]->hasChildren());
?>
以上例程会输出：
bool(true)
bool(false)