tidyNode::hasChildren()
(PHP 5, PHP 7)
检查节点是否有子节点
说明
public tidyNode::hasChildren(void): bool
返回值
Returns TRUE
if the node has children,FALSE
otherwise.
范例
tidyNode::hasChildren() example
<?php $html = <<< HTML <html><head> <?php echo '<title>title</title>'; ?> <# /* JSTE code */ alert('Hello World'); #> </head> <body> <?php // PHP code echo 'hello world!'; ?> <% /* ASP code */ response.write("Hello World!") %> <!-- Comments --> Hello World </body></html> Outside HTML HTML; $tidy = tidy_parse_string($html); $num = 0; // the head tag var_dump($tidy->html() >child[0]->hasChildren()); // the php inside the head tag var_dump($tidy->html() >child[0]->child[0]->hasChildren()); ?>
以上例程会输出:
bool(true)
bool(false)