date_sub()
(PHP 5 >= 5.3.0, PHP 7)
别名DateTime::sub()
说明
此函数是该函数的别名:DateTime::sub()
It can be unclear for someone how to use this function. Here is the example: $date=date_create("2013-03-15"); date_sub($date,date_interval_create_from_date_string("40 days")); echo date_format($date,"Y-m-d");
In version 5.6.31 the variable $ today is passed by reference in the function date_sub () and the interval is also applied <?php $today = date_create(date('Y-m-d')); $yesterday = date_sub($today, date_interval_create_from_date_string("1 days")); echo var_dump($today); echo var_dump($yesterday) ?>
To glue to the OOP, it's better to use it with DateInterval::createFromDateString <?php $dateB = new DateTime('2020-12-20'); $dateA = $dateB->sub(DateInterval::createFromDateString('10 days')); ?> more detail here : <?php public static function createFromDateString ($time) {} ?>
You cannot replace date_sub('2000-01-20') by DateTime::sub('2000-01-20') because DateTime::sub is not static. You have to create the DateTime object first. Example: <?php $dateA = date_sub('2000-01-20', date_interval_create_from_date_string('10 days')); ?> will be replace by <?php $dateB = new DateTime('2000-01-20'); $dateA = $dateB->sub(date_interval_create_from_date_string('10 days')); ?>