getdate()
(PHP 4, PHP 5, PHP 7)
取得日期/时间信息
说明
getdate([int $timestamp= time()]): array
返回一个根据$timestamp得出的包含有日期信息的关联数组array。如果没有给出时间戳则认为是当前本地时间。
参数
- $timestamp
可选的$timestamp参数是一个integer的 Unix时间戳,如未指定,参数值默认为当前本地时间。也就是说,其值默认为time()的返回值。
返回值
返回一个根据$timestamp得出的包含有日期信息的关联数组array。返回的关联数组中的键名单元有以下几个:
键名 | 说明 | 返回值例子 |
---|---|---|
"seconds" | 秒的数字表示 | 0到59 |
"minutes" | 分钟的数字表示 | 0到59 |
"hours" | 小时的数字表示 | 0到23 |
"mday" | 月份中第几天的数字表示 | 1到31 |
"wday" | 星期中第几天的数字表示 | 0(周日)到6(周六) |
"mon" | 月份的数字表示 | 1到12 |
"year" | 4 位数字表示的完整年份 | 比如:1999或2003 |
"yday" | 一年中第几天的数字表示 | 0到365 |
"weekday" | 星期几的完整文本表示 | Sunday到Saturday |
"month" | 月份的完整文本表示,比如 January 或 March | January到December |
0 | 自从 Unix 纪元开始至今的秒数,和time()的返回值以及用于date()的值类似。 | 系统相关,典型值为从-2147483648到2147483647。 |
范例
Example #1getdate()例子
<?php $today = getdate(); print_r($today); ?>
以上例程的输出类似于:
Array ( [seconds] => 40 [minutes] => 58 [hours] => 21 [mday] => 17 [wday] => 2 [mon] => 6 [year] => 2003 [yday] => 167 [weekday] => Tuesday [month] => June [0] => 1055901520 )
参见
date()
格式化一个本地时间/日期idate()
将本地时间日期格式化为整数localtime()
取得本地时间time()
返回当前的 Unix 时间戳setlocale()
设置地区信息
Andre's code will throw an error. for the following line $d = $todayh[mday]; $m = $todayh[mon]; $y = $todayh[year]; "Notice : Undefined constant mday ,mon,year" As is, it was looking for constants called mday, mon, year etc. When it doesn't find such a constant, PHP interprets it as a string. like any other request it should be wrapped in quotes like this $d = $todayh['mday']; $m = $todayh['mon']; $y = $todayh['year'];
In addition to canby23 at ms19 post: It's a very bad idea to consider day having 24 hours (86400 secs), because some days have 23, some - 25 hours due to daylight saving changes. Using of mkdate() and strtotime() is always preferred. strtotime() also has a very nice behaviour of datetime manipulations: <?php echo strtotime ("+1 day"), "\n"; echo strtotime ("+1 week"), "\n"; echo strtotime ("+1 week 2 days 4 hours 2 seconds"), "\n"; echo strtotime ("next Thursday"), "\n"; echo strtotime ("last Monday"), "\n"; ?>
I thought best to show a posseble way to go about bypassing the end month issue where the first day in a new month will have the monday of the week that it falls in - in the old month. Use the numbering of days as the constant and work you way from there. Example: <?php //----------------------------- $now = time(); $num = date("w"); if ($num == 0) { $sub = 6; } else { $sub = ($num-1); } $WeekMon = mktime(0, 0, 0, date("m", $now) , date("d", $now)-$sub, date("Y", $now)); //monday week begin calculation $todayh = getdate($WeekMon); //monday week begin reconvert $d = $todayh[mday]; $m = $todayh[mon]; $y = $todayh[year]; echo "$d-$m-$y"; //getdate converted day ?> Allot less code makes everyone happy..
another gmgetdate that is a little faster/suscint (no loops). <?php function gmgetdate2($ts = null){ $k = array('seconds','minutes','hours','mday', 'wday','mon','year','yday','weekday','month',0); return(array_combine($k,split(":", gmdate('s:i:G:j:w:n:Y:z:l:F:U',is_null($ts)?time():$ts)))); } ?> https://ajawbk.com/
It's worth noting that this is local time, not UTC/GMT - gmgetdate doesn't exist :(. The most logical way to handle date arithmetic without hitting DST problems is to work in UTC... <?php function add_days($my_date,$numdays) { $date_t = strtotime($my_date.' UTC'); return gmdate('Y-m-d',$date_t + ($numdays*86400)); } ?> [it's even faster if you use gmmktime instead of strtotime]
Here is another gmgetdate that is a little faster/suscint (no loops). <?php function gmgetdate2($ts = null){ $k = array('seconds','minutes','hours','mday', 'wday','mon','year','yday','weekday','month',0); return(array_combine($k,split(":", gmdate('s:i:G:j:w:n:Y:z:l:F:U',is_null($ts)?time():$ts)))); } ?> It also returns the values in the same order as getdate.