getdate()

(PHP 4, PHP 5, PHP 7)

取得日期／时间信息

说明

getdate([int $timestamp= time()]): array

返回一个根据$timestamp得出的包含有日期信息的关联数组array。如果没有给出时间戳则认为是当前本地时间。

参数

$timestamp

可选的$timestamp参数是一个integer的 Unix时间戳，如未指定，参数值默认为当前本地时间。也就是说，其值默认为time()的返回值。

返回值

返回一个根据$timestamp得出的包含有日期信息的关联数组array。返回的关联数组中的键名单元有以下几个：

范例

Example #1getdate()例子

<?php
$today = getdate();
print_r($today);
?>

以上例程的输出类似于：

Array
(
    [seconds] => 40
    [minutes] => 58
    [hours]   => 21
    [mday]    => 17
    [wday]    => 2
    [mon]     => 6
    [year]    => 2003
    [yday]    => 167
    [weekday] => Tuesday
    [month]   => June
    [0]       => 1055901520
)

参见

• date() 格式化一个本地时间／日期
• idate() 将本地时间日期格式化为整数
• localtime() 取得本地时间
• time() 返回当前的 Unix 时间戳
• setlocale() 设置地区信息

Andre's code will throw an error. for the following line
  
   $d = $todayh[mday];
   $m = $todayh[mon];
   $y = $todayh[year];
"Notice : Undefined constant mday ,mon,year"
As is, it was looking for constants called mday, mon, year etc. When it doesn't find such a constant, PHP interprets it as a string. 
like any other request it should be wrapped in quotes like this
   $d = $todayh['mday'];
   $m = $todayh['mon'];
   $y = $todayh['year'];

In addition to canby23 at ms19 post:
It's a very bad idea to consider day having 24 hours (86400 secs), because some days have 23, some - 25 hours due to daylight saving changes. Using of mkdate() and strtotime() is always preferred. strtotime() also has a very nice behaviour of datetime manipulations:
<?php
echo strtotime ("+1 day"), "\n";
echo strtotime ("+1 week"), "\n";
echo strtotime ("+1 week 2 days 4 hours 2 seconds"), "\n";
echo strtotime ("next Thursday"), "\n";
echo strtotime ("last Monday"), "\n"; 
?>

I thought best to show a posseble way to go about bypassing the end month issue where the first day in a new month will have the monday of the week that it falls in - in the old month. Use the numbering of days as the constant and work you way from there.
Example:
<?php
//-----------------------------
$now = time();
$num = date("w");
if ($num == 0)
{ $sub = 6; }
else { $sub = ($num-1); }
$WeekMon = mktime(0, 0, 0, date("m", $now) , date("d", $now)-$sub, date("Y", $now));  //monday week begin calculation
$todayh = getdate($WeekMon); //monday week begin reconvert
$d = $todayh[mday];
$m = $todayh[mon];
$y = $todayh[year];
echo "$d-$m-$y"; //getdate converted day
?> 
Allot less code makes everyone happy..

another gmgetdate that is a little faster/suscint (no loops). 
<?php 
function gmgetdate2($ts = null){ 
    $k = array('seconds','minutes','hours','mday', 
        'wday','mon','year','yday','weekday','month',0); 
    return(array_combine($k,split(":", 
        gmdate('s:i:G:j:w:n:Y:z:l:F:U',is_null($ts)?time():$ts)))); 
    } 
?> 
https://ajawbk.com/

It's worth noting that this is local time, not UTC/GMT - gmgetdate doesn't exist :(.
The most logical way to handle date arithmetic without hitting DST problems is to work in UTC...
<?php
function add_days($my_date,$numdays) {
 $date_t = strtotime($my_date.' UTC');
 return gmdate('Y-m-d',$date_t + ($numdays*86400));
}
?>
[it's even faster if you use gmmktime instead of strtotime]

Here is another gmgetdate that is a little faster/suscint (no loops). 
<?php
function gmgetdate2($ts = null){
    $k = array('seconds','minutes','hours','mday',
        'wday','mon','year','yday','weekday','month',0);
    return(array_combine($k,split(":",
        gmdate('s:i:G:j:w:n:Y:z:l:F:U',is_null($ts)?time():$ts))));
    }
?>
It also returns the values in the same order as getdate.