pg_field_name()
(PHP 4 >= 4.2.0, PHP 5, PHP 7)
返回字段的名字
说明
pg_field_name(resource $result,int $field_number): string
pg_field_name()返回给定 PostgreSQL$result资源中的$field_number所代表的字段名。字段编号从 0 开始。
Example #1 获取字段信息
<?php $dbconn = pg_connect("dbname=publisher") or die("Could not connect"); $res = pg_query($dbconn, "select * from authors where author = 'Orwell'"); $i = pg_num_fields($res); for ($j = 0; $j < $i; $j++) { echo "column $j\n"; $fieldname = pg_field_name($res, $j); echo "fieldname: $fieldname\n"; echo "printed length: ".pg_field_prtlen($res, $fieldname)." characters\n"; echo "storage length: ".pg_field_size($res, $j)." bytes\n"; echo "field type: ".pg_field_type($res, $j)." \n\n"; } ?>
上例的输出如下:
column 0 fieldname: author printed length: 6 characters storage length: -1 bytes field type: varchar column 1 fieldname: year printed length: 4 characters storage length: 2 bytes field type: int2 column 2 fieldname: title printed length: 24 characters storage length: -1 bytes field type: varchar
Note:本函数以前的名字为pg_fieldname()。
参见pg_field_num()。
In fact you can extract the size of the varchar field, by simply sending the following query: "select a.atttypmod,a.attrelid from pg_attribute as a, pg_class as c where c.relname='$table' AND a.attrelid=c.oid AND a.attname='$field'" here is a simple function that does that: function get_field_size($table, $field, $link) { $result = pg_query($link, "select a.atttypmod,a.attrelid from pg_attribute as a, pg_class as c where c.relname='$table' AND a.attrelid=c.oid AND a.attname='$field'"); $data = pg_fetch_object($result); return ($data->atttypmod - 4); } returned value is a size of a given field (also varchar)
The pg_fieldname function only returns the unqualified name from the select statement. example: select c.name, con.name from customer c, contacts con where con.customer_id = c.id; pg_fieldname will return "name" for both fields instead of c.name and con.name. This is a PostgreSQL limitation, not a PHP limitation. if you need different field names you should use : select c.name as customer_name, con.name as contact_name from customer c, contacts con where con.customer_id = c.id; then pg_fieldname will return "customer_name" and "contact_name"